[tex]dane:\\m = 3 \ kg\\v = 144\frac{km}{h} = 144\cdot\frac{1000 \ m}{3600 \ s} = 40\frac{m}{s^{2}}\\szukane:\\E_{k} = ?\\\\Rozwiazanie\\\\E_{k} = \frac{1}{2}mv^{2}\\\\E_{k} = \frac{1}{2}\cdot3 \ kg\cdot(40\frac{m}{s})^{2}\\\\E_{k} = 2 \ 400 \ J=2,4 \ kJ\\\\(1 \ kJ = 1000 \ J)[/tex]
Odp. Energia kinetyczna tego ciała Ek = 2,4 kJ
