[tex]dane:\\m = 2 \ kg\\c = 2000\frac{J}{kg\cdot^{o}C}\\\Delta T = 2^{o}C\\szukane:\\E = ?\\\\Rozwiazanie\\\\E = Q = c\cdot m\cdot \Delta T\\\\Q = 2000\frac{J}{kg\cdot^{o}C}\cdot2 \ kg\cdot2^{o}C\\\\Q = 8 \ 000 \ J = 8 \ kJ\\\\(1 \ kJ = 1000 \ J)[/tex]
Odp. Trzeba dostarczyć 8 kJ energii.
