Pomoże ktoś? Dam naj

a)
[tex] \frac{(4x - 2)}{(2x - 1)(x - 2)} = 0 [/tex]
[tex]4x - 2 = 0[/tex]
[tex]4x = 2[/tex]
[tex]x = \frac{1}{2} [/tex]
b)
[tex] \frac{x(3x - 4)}{x - 3} = 0[/tex]
[tex]x(3x - 4) = 0[/tex]
[tex]x = 0 \: \: lub \: \: 3x - 4 = 0 \\ x = 0 \: \: lub \: \: 3x = 4 \\ x = 0 \: \: lub \: \: x = \frac{4}{3} [/tex]
c)
[tex] {x}^{2} - 16 = 0[/tex]
[tex](x - 4)(x + 4) = 0[/tex]
[tex]x - 4 = 0 \: \: lub \: \: x + 4 = 0 \\ x = 4 \: \: lub \: \: x = - 4[/tex]
d)
[tex](x + 16)(x + 4) = 0[/tex]
[tex]x + 16 = 0 \: \: lub \: \: x + 4 = 0 \\ x = - 16 \: \: lub \: \: x = - 4[/tex]