Odpowiedź:
zadanie 4
H=9cm
[tex]a\sqrt{3} =9 |:\sqrt{3}\\a=\frac{9}{\sqrt{3} }\\\frac{9}{\sqrt{3} } * \frac{\sqrt{3} }{\sqrt{3} }=\frac{^{3\sqrt{3} } }{1} } = 3\sqrt{3} [cm]\\Pp= \frac{a^{2}\sqrt{3} }{4} = \frac{(3\sqrt{3})^{2} }{4} = \frac{27\sqrt{3} }{4} [cm^{2}]\\V =Pp * H = \frac{27\sqrt{3} }{4} *9 = \frac{243\sqrt{3} }{4} [cm^{3}][/tex]
zadanie 5
h=10cm
[tex]a^{2} =26^{2} -10^{2} \\a^{2} = 676 -100 = 576 \\a = \sqrt{576} = 24[cm]\\2a=3*24=48[cm]\\Pp= \frac{10*48}{1} = 480[cm^{2}]\\V=Pp*H=480*10=4800[cm^{3}]\\V=4800cm^{3} = 4800*1cmx^{3} =4800 *0,001dm^{3} =4,8dm^{3}[/tex]
Szczegółowe wyjaśnienie:
