[tex]x = \frac{12^{6\sqrt{3} } }{2^{1} }[/tex] (skreśl w tym 12 i 2)
[tex]y = \frac{2}{3} x = \frac{2}{3^{1} } * 6^{2} \sqrt{3} cm = 4\sqrt{3} cm[/tex] (skreśl w drugim ułamku 3 i 6)
[tex]h^{2} +y^{2} = 10^{2} \\h^{2} + (4\sqrt{4*13} = 2\sqrt{13} cm \\h^{2} + 48 = 100\\h^{2} = 52\\h = \sqrt{52} = \sqrt{4 * 13} =2\sqrt{13} cm[/tex]
