Odpowiedź:
6(x-4)-2=6x-24-2=6x-26
2(x+1)-3(x-1)=2x+2-3x-3=-x-1
-3(y-2)+4(y+2)-3y+6+4y+2=y+8
5(x-y-1)-4(x+2)=5x-5y-5-4x-2=x-5y-7
2(3a+b)-2(a-b)=6a+2b-2a+2b=4a+4b
0,5(4x-4)-2x=2x-2-2x=-2
[tex]x(x-1)-3(x^{2} -x)=x^{2} +x-3x^{2} +3x=-2x^{2} +4x[/tex]
[tex]5a(a-3)-3a(a-5)=5a^{2}-15-3a^{2} +15=2a^{2}[/tex]
[tex]\frac{3x-6}{3} -5=x-7[/tex]
[tex]\frac{3a-9b}{3} -\frac{2a-4b}{2} = -b[/tex]
[tex]\frac{2x+6}{2} -\frac{6x-9}{3} = -x+6[/tex]
[tex]4*\frac{x-7}{2} +9*\frac{x-1}{3} = 5x-17[/tex]
[tex](x+7)(2x-1)=2x^{2} -x+14x-7=2x^{2}+13x-7[/tex][tex](2a-1)(a+4)=2a^{2} +8a-a-4=2a^{2}+7a-4[/tex]
[tex](4a-1)(2-3a)=8a-12a^{2} -2+3a=11a-12a^{2} -2[/tex]
[tex](2k^{2}-1 )(2k+1)-4k^{3} = 2k^{2}-2k-1\\(3p^{2}-p)(3-p)= -3p^{3}+10^{2}-3p\\(a-b)(a^{2}+ab+b^{2})=a^{3}-b^{3} \\(a+b)(a^{2}-ab+b^{2})=a^{3}+b^{3}[/tex]
