Odpowiedź :
I. 2n+1
II. 2n+1+2 = 2n+3
III. 2n+3+2= 2n+5
[tex] \frac{2n + 1 + 2n + 3 + 2n + 5}{3} = \frac{6n + 9}{3} = \frac{3(2n + 3)}{3} = 2n + 3[/tex]
I. 2n+1
II. 2n+1+2 = 2n+3
III. 2n+3+2= 2n+5
[tex] \frac{2n + 1 + 2n + 3 + 2n + 5}{3} = \frac{6n + 9}{3} = \frac{3(2n + 3)}{3} = 2n + 3[/tex]