Odpowiedź :
[tex]dane:\\s = 80 \ km\\v = 42\frac{km}{h}\\szukane:\\t = ?\\\\s = v\cdot t \ \ /:v\\\\t = \frac{s}{v}\\\\t = \frac{80 \ km}{42\frac{km}{h}}\\\\t \approx 1,9 \ h[/tex]
[tex]dane:\\s = 80 \ km\\v = 42\frac{km}{h}\\szukane:\\t = ?\\\\s = v\cdot t \ \ /:v\\\\t = \frac{s}{v}\\\\t = \frac{80 \ km}{42\frac{km}{h}}\\\\t \approx 1,9 \ h[/tex]