Odpowiedź :
[tex]1)\\dla \ \ x = -2\\\\3x^{2}+2x-7 = 3\cdot(-2)^{2}+2\cdot(-2) - 7 = 3\cdot4-4-7 = 12-11 = 1[/tex]
[tex]2)\\dla \ \ k = -2 \ \ i \ \ z = 2\\\\-5k^{2}-3z-2 = -5\cdot(-2)^{2}-3\cdot2-2 = -5\cdot4-6-2 = -20-8 = -28[/tex]
[tex]1)\\dla \ \ x = -2\\\\3x^{2}+2x-7 = 3\cdot(-2)^{2}+2\cdot(-2) - 7 = 3\cdot4-4-7 = 12-11 = 1[/tex]
[tex]2)\\dla \ \ k = -2 \ \ i \ \ z = 2\\\\-5k^{2}-3z-2 = -5\cdot(-2)^{2}-3\cdot2-2 = -5\cdot4-6-2 = -20-8 = -28[/tex]