Odpowiedź:
(2x-2)/(x+2)= x/(x-1) /*(x+2)(x-1)
(2x-2)(x-1)= x(x+2)
2x²-2x-2x+2= x²+2x
2x²-x²-4x+2=0
x²-4x+2=0
a= 1 b= -4 c= 2
Δ= b²-4ac= (-4)²-4·1·2= 16-8= 8
√Δ= √8= 2√2
x1= (-b-√Δ)/2a= (4- 2√2)/2= 2(2-√2)/2= 2- √2
x2= (-b+√Δ)/2a= (4+2√2)/2= 2( 2+√2)/2= 2+√2
Szczegółowe wyjaśnienie:
