Odpowiedź :
[tex]ane:\\P = 200 \ kW = 200 \ 000 \ W\\t = 0,5 \ min = 30 \ s\\szukane:\\W = ?\\\\Rozwiazanie\\\\P = \frac{W}{t} \ \ /\cdot t\\\\W = P\cdot t\\\\W = 200000 \ W\cdot30 \ s\\\\W = 6 \ 000 \ 000 \ J = 6000 \ kJ\\\\(1 \ kJ = 1000 \ J)[/tex]