Odpowiedź:
[tex]1.\\\\0,2x=15\ \ /:0,2\\\\x=75\\\\\\2.\\\\-3x+7=-4x-2\\\\-3x+4x=-2-7\\\\x=-9\\\\\\3.\\\\-7(x-2)=3x-1\\\\-7x+14=3x-1\\\\-7x-3x=-1-14\\\\-10x=-15\ \ /:(-10)\\\\x=1,5\\\\\\4.\\\\\frac{5}{6}(x-1)=4\\\\\frac{5}{6}x-\frac{5}{6}=4\ \ /*6\\\\5x-5=24\\\\5x=24+5\\\\5x=29\ \ /:5\\\\x=\frac{29}{5}\\\\x=5\frac{4}{5}[/tex]
[tex]5.\\\\\frac{x+5}{4}-\frac{2x+1}{8}=\frac{1}{2}(2-x)\ \ /*8\\\\2(x+5)-(2x+1)=4(2-x)\\\\2x+10-2x-1=8-4x\\\\9=8-4x\\\\4x=8-9\\\\4x=-1\ \ /:4\\\\x=-\frac{1}{4}\\\\\\6.\\\\(4-5x)(2+x)=-4(4+5x^2)\\\\8+4x-10x-5x^2=-16-20x^2\\\\8-6x-5x^2+16+20x^2\\\\15x^2-6x+24=0\ \ /:3\\\\5x^2-2x+8=0\\\\\Delta=b^2-4ac=(-2)^2-4*5*8=4-160=-156\\\\\Delta<0\ \ brak\ \ rozwiazania[/tex]
