👤
Rozwiązane

[tex]\frac{3x+5}{6}-\frac{6x+2}{4} -2=0\\\frac{3x}{4} -\frac{100-5x}{6} =29\\\frac{x-3}{4} +\frac{x-4}{3} =\frac{x-5}{2}-\frac{x-4}{8} \\\frac{2x+3}{5} +\frac{4x-1}{10} =\frac{x}{2} \\[/tex]

Rozwiąż równania

Odpowiedź :

123BODZIOON

Odpowiedź:

(3x + 5)/6 - (6x + 2)/4 - 2 = 0 | * 12

2(3x + 5) - 3(6x + 2) - 24 = 0

6x + 10 - 18x - 6 - 24 = 0

- 12x - 20 = 0

- 12x = 20

12x = - 20

x = - 20/12 = - 1 8/12 = - 1 2/3

3x/4 - (100 - 5x)/6 = 29  | * 12

3 * 3x - 2(100 - 5x) = 348

9x - 200 + 10x = 348

19x = 348 + 200 = 548

x = 548/19 = 28 16/29

(x - 3)/4 + (x - 4)/3 = (x - 5)/2 - (x - 4)/8 | * 24

6(x - 3) + 8(x - 4) = 12(x - 5) - 3(x - 4)

6x - 18 + 8x - 32 = 12x - 60 - 3x + 12

14x - 50 = 9x - 48

14x - 9x = - 48 + 50

5x = 2

x = 2/5

(2x + 3)/5 + (4x - 1)/10 = x/2  | * 20

4(2x + 3) + 2(4x - 1) = 10x

8x + 12 + 8x - 2 = 10x

16x + 10 = 10x

16x - 10x = - 10

6x = - 10

x = - 10/6 = - 1 4/6 = - 1 2/3

On Studier: Inne Pytanie