Odpowiedź:
[tex]i)\\\\\frac{3}{5}x=18\ \ /:\frac{3}{5}\\\\x=\not18^6\cdot\frac{5}{\not3_{1}}\\\\x=6\cdot5\\\\x=30\\\\\\j)\\\\-2x=17\ \ /:(-2)\\\\x=-\frac{17}{2}\\\\x=-8\frac{1}{2}[/tex]
[tex]k)\\\\-1\frac{1}{3}x=\frac{20}{3}\\\\-\frac{4}{3}x=\frac{20}{3}\ \ /:(-\frac{4}{3})\\\\x=-\frac{\not20^5}{\not3_{1}}*\frac{\not3^1}{\not4_{1}}\\\\x=-5\\\\\\l)\\\\8,5x=-10\ \ /:8,5\\\\x=-10:\frac{85}{10}\\\\x=-\not10^2\cdot\frac{10}{\not85_{17}}\\\\x=-\frac{20}{17}\\\\x=-1\frac{3}{17}[/tex]
