Zadanie jest w załączniku z fizyki

[tex]dane:\\m_1 = 1 \ kg\\m_2 = 2 \ kg\\m_3 = 4 \ kg\\g = 10\frac{N}{kg}\\\\F = m\cdot g\\\\F_1 = m_1\cdot g = 1 \ kg\cdot10\frac{N}{kg} = 10 \ N\\\\F_2 = m_2\cdot g = 2 \ kg\cdot10\frac{N}{kg} = 20 \ N\\\\F-3 = m_3\cdot g = 4 \ kg\cdot10\frac{N}{kg} = 40 \ N\\\\Odp. \ A).[/tex]