[tex]a)\\\\ \frac{(2^2)^3}{4*2^3}=\frac{2^6}{2^2*2^3}=\frac{2^6}{2^{2+3} }=\frac{2^6}{2^{5} }=2^{6-5}=2^{1}=2\\\\b)\\\\(2^{2}+3^{2})^2=(4+9)^2=13^2=169\\\\c)\\\\2*5^3+3*5^3=5^3(2+3)=5^3*5=5^{3+1}=5^4= 625\\\\d)\\\\\frac{6^5}{3^3*2^3}=\frac{6^5}{(3 *2)^3}=\frac{6^5}{6^3}=6^{5-3}=6^2=36[/tex]
[tex](a^n)^m=a^{n*m}\\\\a^n*a^m=a^{n+b}\\\\a^n:a^m=a^{n-b}\\\\a^n*b^n=(a*b)^n[/tex]
Odpowiedź:
a)
(2²)³/(4 * 2³) = 2^6/(2²*2³) = 2^6 : 2^5 = 2^1 = 2
b)
(2² + 3²)² = (4 + 9)² = 13² = 169
c)
2 * 5³ + 3 * 5³ = 5³(2 + 3) = 5³ * 5 = 5^4 = 625
d)
6^5/(3³ * 2³) = 6^5 : (3 * 2)³ = 6^5 : 6³ = 6² = 36
Szczegółowe wyjaśnienie:
