zad. 7
[tex] {3}^{8} \times {3}^{12} = {3}^{8 + 12} = {3}^{20} \\ ( {3}^{7} {)}^{3} = {3}^{7 \times 3} = {3}^{21} \\ \frac{ {6}^{10} }{ {2}^{10} } = ( \frac{6}{2} {)}^{10} = {3}^{10} \\ ( \frac{1}{3} {)}^{22} \times {9}^{22} = {3}^{ - 22} \times ( {3}^{2} {)}^{22} = {3}^{ - 22} \times {3}^{44} = {3}^{22} [/tex]
odp. D
