Pomocy daje naj za odp

Odpowiedź:
a) 4√16 - 2[tex]\sqrt[4]{625}[/tex] + 3∛27=
= 4*4 - 2*5 + 3*3 =
= 16-10+9 = 15
b) 5[tex]\sqrt[7]{1}[/tex] - 3∛64 + 2√121 =
= 5*1 - 3*4 + 2*11 =
= 5-12+22 = 15
c) 3 * (5√(-6)² + 3∛-125³ + 2[tex]\sqrt[4]{81}[/tex] )=
= 3* [ 30 - 15 + 6 ] =
= 3* 21 = 63