Odpowiedź :
[tex]dane:\\m = 80 \ kg\\h = \frac{1}{2} \ m =0,5 \ m\\t = 2 \ s\\g = 10\frac{N}{kg}\\szukane:\\P = ?\\\\P = \frac{W}{t}\\\\W = E_{p} = mgh \\\\P = \frac{mgh}{t}\\\\P = \frac{80 \ kg\cdot10\frac{N}{kg}\cdot0,5 \ m}{2 \ s}\\\\P = 200 \ W[/tex]
Odp. Moc ciężarowca P = 200 W.