[tex]k=(-7;2), m=(3;-4) \\\\obliczamy\ dlugosc\ przekatnej :\\\\|km|=\sqrt{(x_{m}-x_{k})^2+(y_{m}-y_{k})^2}\\\\|km|=\sqrt{( 3+7)^2+(-4-2 )^2}= \sqrt{10^2+(-6 )^2}=\sqrt{100+36}=\sqrt{136}=\\\\=\sqrt{4*34}=2\sqrt{34}\\\\obliczamy\ bok\ kwadratu:\ \ a=?[/tex]
[tex]przekatna\ kwadratu\ wyraza\ sie\ wzorem:\\\\d=a\sqrt{2}\\\\a\sqrt{2}=2\sqrt{34}\ \ |:\sqrt{2}\\\\a=\frac{2\sqrt{34}}{\sqrt{2}}=2\sqrt{\frac{34}{2}}=2\sqrt{17}\\\\pole\ kwadratu :\\\\P=a^2=(2\sqrt{17})^{2}=4*17=68\ [j^{2}]\\\\obwod\ kwadratu :\\\\L=4a\\\\L=4*2\sqrt{17}=8\sqrt{17}[/tex]
