Odpowiedź:
a)
[tex] |AB| = \sqrt{(3 + 1 {)}^{2} + (2 +2 {)}^{2} } = \sqrt{ {4}^{2} + {4}^{2} } = \sqrt{16 + 16} = \sqrt{32} = 4 \sqrt{2} [/tex]
b)
|BC|
[tex]( \frac{3 - 2}{2} ; \frac{2 + 4}{2} ) = ( \frac{1}{2} ; \frac{8}{2} ) = ( \frac{1}{2} ;4)[/tex]
