Odpowiedź :
Odpowiedź:
[tex](4a-3)(3a+2)-a(a-1)=12a^2+8a-9a-6-a^2+a=11a^2-6\\\\\\dla\ \ a=-\frac{1}{2}\\\\11a^2-6=11*(-\frac{1}{2})^2-6=11*\frac{1}{4}-6=\frac{11}{4}-6=\frac{11}{4}-\frac{24}{4}=-\frac{13}{4}=-3\frac{1}{4}[/tex]
Odpowiedź:
[tex](4a-3)(3a+2)-a(a-1)=12a^2+8a-9a-6-a^2+a=11a^2-6\\\\\\dla\ \ a=-\frac{1}{2}\\\\11a^2-6=11*(-\frac{1}{2})^2-6=11*\frac{1}{4}-6=\frac{11}{4}-6=\frac{11}{4}-\frac{24}{4}=-\frac{13}{4}=-3\frac{1}{4}[/tex]