Hej!
[tex]\frac{x-3}{x+4}=\frac{x-2}{x-1}\\\\x+4\neq0\rightarrow x\neq-4\\\\x-1\neq0\rightarrow x\neq1\\\\(x-3)(x-1)=(x+4)(x-2)\\\\x^2-x-3x+3=x^2-2x+4x-8\\\\x^2-4x+3=x^2+2x-8\\\\x^2-4x-x^2-2x=-8-3\\\\-6x=-11 \ \ \:(-6)\\\\x=\frac{11}{6}=1\frac{5}{6}\in\mathbb{D}[/tex]
