[tex]Zadanie\\\\\frac{\sqrt[4]{81}+\sqrt[3]{2\frac{10}{27} } }{1+(1\frac{1}{2})^{-2} }= \frac{3+\sqrt[3]{\frac{64}{27} } }{1+(\frac{3}{2}) ^{-2} }=\frac{3+\frac{4}{3} }{1+(\frac{2}{3})^{2} }=\frac{4\frac{1}{3} }{1+\frac{4}{9} }=\frac{\frac{13}{3} }{\frac{13}{9} }=\frac{13}{3} \cdot \frac{9}{13}=\frac{9}{3}=3[/tex]
