Zad. 4
[tex]\frac{5}{12} a +2,5 = 4\frac{2}3} \\ \frac{5}{12} a +2,5 = \frac{14}{3} \ \ \ \ |\cdot 12 \\ 5a + 30 = 56 \\5a = 56-30 \\ 5a = 26 \ \ \ |:5 \\ a = 5,2 \\\\ Sprawdzenie: \\ L = \frac{5}{12} \cdot 5,2 +2,5 =\frac{5}{12} \cdot \frac{52}{10}+\frac{25}{10} = \frac{\not{5}^1}{\not{12}_6} \cdot \frac{\not{26}^{13}}{\not{5}_1}+\frac{5}{2} =\frac{13}{6} +\frac{15}{6} =\frac{28}{6} =\frac{14}{3} =4\frac{2}{3} \\ P = 4\frac{2}{3} \\ L = P[/tex]
Odp. a = 5,2
