[tex]dane:\\a = 6 \ cm\\V = a^{3} = (6 \ cm)^{3} = 216 \ cm^{3} = 0,000216 \ m^{3}\\d = 920\frac{kg}{m^{3}}\\g = 10\frac{N}{kg}\\szukane:\\F_{w} = ?\\\\Rozwiazanie\\\\F_{w} = d\cdot g\cdot V\\\\F_{w} = 920\frac{kg}{m^{3}}\cdot10\frac{N}{kg}\cdot0,000216 m^{3}\\\\F_{w} = 1,9872 \ N \approx 2 \ N[/tex]
