Odpowiedź:
e)
[tex] \frac{4}{5 \sqrt{3} } = \frac{4 \times \sqrt{3} }{5 \sqrt{3} \times \sqrt{3} } = \frac{4 \sqrt{3} }{5 \times 3} = \frac{4 \sqrt{3} }{15} [/tex]
f)
[tex] \frac{9}{2 \sqrt{6} } = \frac{9 \times \sqrt{6} }{2 \sqrt{6} \times \sqrt{6} } = \frac{9 \sqrt{6} }{2 \times 6} = \frac{9 \sqrt{6} }{12} = \frac{3 \sqrt{6} }{4} [/tex]
