Odpowiedź :
[tex]2+2+2:3 - 3 + 444:22 = 4+\frac{2}{3}-3 + \frac{444}{22} = 1+\frac{2}{3}+\frac{222}{11} = 1+\frac{2}{3}+20\frac{2}{11} =\\\\=1+\frac{22}{33}+20\frac{6}{33} = 21\frac{28}{33}[/tex]
[tex]2+2+2:3 - 3 + 444:22 = 4+\frac{2}{3}-3 + \frac{444}{22} = 1+\frac{2}{3}+\frac{222}{11} = 1+\frac{2}{3}+20\frac{2}{11} =\\\\=1+\frac{22}{33}+20\frac{6}{33} = 21\frac{28}{33}[/tex]