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Zapisz w najprostszej formie

10x^3 + 6 ( x^2 - 2 )

---------------------------- - 2x ( 3 - 2x - x^2

2


Odpowiedź :

[tex]\frac{10x^3+6(x^2-2)}{2} -2x(3-2x-x^2) = \frac{10x^3+6x^2-12}{2} -6x+4x^2+2x^3 = \\\\ = \frac{\not{2}^1(5x^3+3x^2-6)}{\not{2}_1} -6x+4x^2+2x^3 =5x^3+3x^2-6-6x+4x^2+2x^3 = 7x^3+7x^2-6x-6[/tex]