Odpowiedź:
[tex]a)\ \ 4*1\frac{1}{5}=4*(1+\frac{1}{5})=4*1+4*\frac{1}{5}=4+\frac{4}{5}=4\frac{4}{5}\\\\b)\ \ 2\frac{3}{7}*6=(2+\frac{3}{7})*6=2*6+\frac{3}{7}*6=12+\frac{18}{7}=12+2\frac{4}{7}=14\frac{4}{7}\\\\c)\ \ 2\frac{5}{6}*3=(2+\frac{5}{6})*3=2*3+\frac{5}{\not6_{2}}*\not3^1=6+\frac{5}{2}=6+2\frac{1}{2}=8\frac{1}{2}\\\\d)\ \ 8\frac{2}{9}*6=(8+\frac{2}{9})*6=8*6+\frac{2}{\not9_{3}}*\not6^2=48+\frac{4}{3}=48+1\frac{1}{3}=49\frac{1}{3}[/tex]
