Odpowiedź:
111
A)
[tex] - 1 \frac{1}{5} \div \binom{2}{3 } ^{2} = - \frac{6}{5} \div \frac{4}{9} = - \frac{2}{5} \div \frac{4}{3} = \frac{2}{5} \times \frac{3}{4} = 8 \\ \frac{8}{20} \times \frac{15}{20} = \frac{23}{20} = 1 \frac{3}{20} [/tex]
