Odpowiedź :
[tex]dane:\\m = 50 \ kg\\a = 2\frac{m}{s^{2}} = 2\frac{N}{kg}\\szukane:\\F = ?\\\\Rozwiazanie\\\\Z \ II \ zasady \ dynamiki\\\\a = \frac{F}{m} \ \ |\cdot m\\\\F = m\cdot a\\\\F = 50 \ kg\cdot2\frac{N}{kg} = 100 \ N\\\\Odp. \ b)[/tex]
[tex]dane:\\m = 50 \ kg\\a = 2\frac{m}{s^{2}} = 2\frac{N}{kg}\\szukane:\\F = ?\\\\Rozwiazanie\\\\Z \ II \ zasady \ dynamiki\\\\a = \frac{F}{m} \ \ |\cdot m\\\\F = m\cdot a\\\\F = 50 \ kg\cdot2\frac{N}{kg} = 100 \ N\\\\Odp. \ b)[/tex]