Odpowiedź:
4x²- 4x+1 +1 ≥ 3x - 2
4x²-4x+1-3x+2 ≥ 0
4x²-7x+3 ≥ 0
x (4x - 3) - (4x - 3) ≥ 0
(4x-3) (x-1) ≥ 0
4x-3≥0 ∪ x-1≥0
4x ≥ 3 x≥1
x ≥ 3/4
x∈ (-∞,3/4> ∪ <1,∞)
