[tex]a)\\\\\frac{5}{9}\cdot 7 - \frac{8}{12} = \frac{35}{9}-\frac{2}{3} = \frac{35}{9}-\frac{6}{9} = \frac{29}{9} = 3\frac{2}{9}}[/tex]
[tex]b)\\\\\frac{1}{5}+\frac{3}{7}\cdot3 = \frac{1}{5}+\frac{9}{7} = \frac{7}{35}+\frac{45}{35} = \frac{52}{35} = 1\frac{17}{35}[/tex]
