Odpowiedź :
Odpowiedź:
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Szczegółowe wyjaśnienie:
a) [tex](\sqrt{2}+3)(\sqrt{2} -1)=2-\sqrt{2} +3\sqrt{2} -3= -1+2\sqrt{2}[/tex]
b) [tex](\sqrt{5} -2)(\sqrt{5} -3)=5-3\sqrt{5} -2\sqrt{5} +6=11-5\sqrt{5}[/tex]
c) [tex](\sqrt{3} -\sqrt{2} )(\sqrt{3}-2\sqrt{2} )= 3-2\sqrt{6} -\sqrt{6} +4=7-3\sqrt{6}[/tex]
d) [tex](2\sqrt{5} +\sqrt{2} )(\sqrt{5} +3\sqrt{2})=10+6\sqrt{10} +\sqrt{10} +6=16+7\sqrt{10}[/tex]
e) [tex](\sqrt{3} +\sqrt{2} )(\sqrt{3} +\sqrt{2} -1)= 3 +\sqrt{6} -\sqrt{3} +\sqrt{6} +2 -\sqrt{2} = 5+2\sqrt{6} -\sqrt{3} -\sqrt{2}[/tex]
f) [tex](\sqrt{3} -\sqrt{2})(\sqrt{6}-\sqrt{3}+\sqrt{2} )=3\sqrt{2} -3+\sqrt{6} -2\sqrt{3} +\sqrt{6} -2= -5+ 3\sqrt{2} +2\sqrt{6} -2\sqrt{3}[/tex]