Odpowiedź:
Szczegółowe wyjaśnienie:
2x²-2x-12=0 /:2
x²-x-6=0
Δ=1+24 = 25
√Δ = 5
[tex]x_{1}[/tex] = [tex]\frac{1-5}{2}[/tex] = [tex]\frac{-4}{2}[/tex] = -2
[tex]x_{2}[/tex] = [tex]\frac{1+5}{2}[/tex] = [tex]\frac{6}{2}[/tex] = 3
2x^2 - 2x - 12 = 0 /:2
x^2 - x - 6 = 0
Delta = (-1)^2 - 4 * 1 * (-6) = 25
x1 = (1-5)/2 = -2
x2 = (1+5)/2 = 3
