Odpowiedź:
[tex]-2(3y-5)^2-(1+\sqrt{5}y)(\sqrt{5}y-1)=-2(9y^2-30y+25)-(\sqrt{5}y+1)(\sqrt{5}y-1)=\\\\=-18y^2+60y-50-(5y^2-1)=-18y^2+60y-50-5y^2+1=-23y^2+60y-49\\\\\\dla\ \ y=-1\\\\-23y^2+60y-49=-23*(-1)^2+60*(-1)-49=-23*1-60-49=\\\\=-23-60-49=-132[/tex]
