Zadanie 1
a) C4H8- buten
CH2=CH-CH2-CH3
b) C3H4- propyn
CH≡C-CH3
Zadanie 2
mC2H6=2*12u+6*1u
Stosunek masowy:
mC:mH=24:6=4:1
Zadanie 3
mC3H6=3*12u+6*1u=42u
36u---x%
42u---100%
x=85,71%C
Zadanie 4
C3H4+4O2--->3CO2+2H2O
2C3H4+5O2--->6CO+4H2O
C3H4+O2--->3C+2H2O
