Odpowiedź:
[tex]\dfrac{\sqrt{7}*7*\sqrt[3]{7}}{7^2*7^{-3}}=\dfrac{7^{\frac{1}{2}}*7*7^{\frac{1}{3}}}{7^{2+(-3)}}=\dfrac{7^{\frac{1}{2}+1+\frac{1}{3}}}{7^{2-3}}=\dfrac{7^{\frac{3}{2}+\frac{1}{3}}}{7^{-1}}=\dfrac{7^{\frac{9}{6}+\frac{2}{6}}}{7^{-1}}=\dfrac{7^{\frac{11}{6}}}{7^{-1}}=7^{\frac{11}{6}-(-1)}=\\\\\\=7^{\frac{11}{6}+1}=7^{\frac{17}{6}[/tex]
