[tex]dane:\\F_{w} = 30 \ mN = 0,03 \ N\\a = 6\frac{m}{s^{2}} = 6\frac{N}{kg}\\szukane:\\m = ?\\\\Rozwiazanie\\\\Z \ II \ zasady \ dynamiki\\\\a = \frac{F_{w}}{m} \ \ /\cdot m\\\\m\cdot a = F_{w} \ \ /:a\\\\m = \frac{F_{w}}{a}\\\\m = \frac{0,03 \ N}{6\frac{N}{kg}}} = 0,005 \ kg = 5 \ mg[/tex]
Odp. Masa tej monety m = 5 mg.
