[tex]d_1 = 3 \ dm\\d_2 = 40 \ cm = 4 \ dm\\\\P = \frac{d_1\cdot d_2}{2} = \frac{3 \ dm\cdot 4 \ dm}{2} = 6 \ dm^{2} = 600 \ cm^{2}[/tex]
Hej!
Oto Twoja odpowiedź:
[tex]pole \: rombu \: = \: \frac{e \times f}{2} [/tex]
e = 3 dm = 30 cm
f = 40 cm
[tex]p = \frac{30cm \times 40cm}{2} = \frac{1200cm}{2} = 600 {cm}^{2} [/tex]
Odpowiedź: Pole tego rombu wynosi 600 cm2.
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