Odpowiedź:
zad 1
a)
2caabb = 2a²b²c
b)
6a * (- 2) * b * (- 3/4) * c = 36abc/4 = 9abc
zad 2
a)
3x - 4y + 5x + 6y = 8x + 2y
b)
2(x² - x + 3) - 5x(x + 1) + 3x² + 5 = 2x² - 2x + 6 - 5x² - 5x + 3x² + 5 =
= - 7x + 11
zad 3
(x + 5)² = x² + 10x + 25
(2a - 3b)² = 4a² - 12ab + 9b²
(√2 + 1)(√2 - 1) = (√2)² - 1² = 2 - 1 = 1
