[tex]5)\\\\\sqrt{5}*\sqrt{12\frac{4}{5}}-2^7:2^5=\sqrt{5}*\sqrt{ \frac{64}{5}}-2^{7-5}=\sqrt{\not{5}^1 *\frac{64}{\not{5}^1}}-2^2=\sqrt{64}-4=8-4=4\\\\\\6)\\\\\frac{1,5*\frac{3}{5}}{1,5-\frac{3}{5}}=\frac{\frac{\not{15}^3}{ 10}*\frac{3}{\not{5}^1}}{\frac{15}{10}-\frac{3}{5}}=\frac{\frac{9}{10} }{\frac{15}{10}-\frac{6}{10}}=\frac{\frac{9}{10} }{\frac{9}{10} }=1\\\\\\b)\\\\\sqrt{2\frac{7}{9}}*3+\frac{3}{4}:(-1\frac{1}{2})^3 =\sqrt{ \frac{25}{9}}*3+\frac{3}{4}:(- \frac{3}{2})^3 =\frac{5}{\not{3}^1}*\not{3}^1+\frac{3}{4}:(- \frac{27}{8}) =\\\\=5+\frac{\not{3}^1}{\not{4}^1}*(- \frac{\not{8}^2}{\not{27}^9})=5-\frac{2}{9}=4\frac{5}{9}[/tex]
