Hej!
Równanie :
[tex]\frac{x+2}{3}-\frac{x-3}{9}=\frac{x}{6}+2 \ \ |\cdot18\\\\6(x+2)-2(x-3)=3x+36\\\\6x+12-2x+6=3x+36\\\\6x-2x-3x=36-12-6\\\\\huge\boxed{x=18}[/tex]
Nierówność :
[tex]3(x-1)^2-(x-\sqrt5)(x+\sqrt5)\geq3x^2-(x+4)(x-1)\\\\3(x^2-2x+1)-(x^2-5)\geq3x^2-(x^2-x+4x-4)\\\\3x^2-6x+3-x^2+5\geq3x^2-x^2+x-4x+4\\\\2x^2-6x+8\geq2x^2-3x+4\\\\2x^2-6x-2x^2+3x\geq4-8\\\\-3x\geq-4 \ \ |:(-3)\\\\x\leq\frac{4}{3}\\\\\huge\boxed{x\in(-\infty;\frac{4}{3}\rangle}[/tex]
