[tex]dane:\\m = 10 \ kg\\a = 3\frac{m}{s^{2}}\\\mu = 0,4\\g = 10\frac{m}{s^{2}}\\szukane:\\F = ?\\\\Rozwiazanie\\\\F_{w} = F - T \ \ \rightarrow \ \ F = F_{w}+T\\\\Z \ II \ zasady \ dynamiki:\\F_{w} = m\cdot a = 10 \ kg\cdot3\frac{m}{s^{2}} = 30 \ N\\\\T = \mu\cdot m\cdot g = 0,4\cdot10 \ kg\cdot10\frac{m}{s^{2}} = 40 \ N\\\\F = F_{w}+T\\\\F = 30 \ N + 40 \ N=70 \ N[/tex]
Odp. Na ten klocek działa siła pozioma F = 70 N.
