Odpowiedź :
Hej!
[tex]x^2-2y=3^2-2\cdot(-5)=9+10=19\\\\x^2+y^2=(\frac{3}{5})^2+(\frac{1}{2})^2=\frac{9}{25}+\frac{1}{4}=\frac{36}{100}+\frac{25}{100}=\frac{61}{100}[/tex]
Pozdrawiam! - Julka
Hej!
[tex]x^2-2y=3^2-2\cdot(-5)=9+10=19\\\\x^2+y^2=(\frac{3}{5})^2+(\frac{1}{2})^2=\frac{9}{25}+\frac{1}{4}=\frac{36}{100}+\frac{25}{100}=\frac{61}{100}[/tex]
Pozdrawiam! - Julka