Odpowiedź:
zad. 1
[tex]a) \sqrt{121} = 11 \\ b) \sqrt[3]{ - 8} = - \sqrt[3]{8} = - 2 \\ c) \frac{ \sqrt{16} }{ \sqrt{49} } = \frac{4}{7} \\ d) \sqrt[3]{27} \times \sqrt[3]{64} = 3 \times 4 = 12[/tex]
zad. 2
[tex] \sqrt{( - 5 {)}^{2} } = \sqrt{25} = 5[/tex]
P
[tex]( \sqrt[3]{( - 6 {)}^{2} {)}^{3} } = \sqrt{( - 6 {)}^{2} } = \sqrt{36} = 6[/tex]
F
Zad. 3
odp. D
zad. 4
[tex] \sqrt[3]{ \sqrt{49} + 1 } = \sqrt[3]{7 + 1} = \sqrt[3]{8} = 2[/tex]
zad. 5
[tex] \sqrt{ \frac{9}{25}} \times \sqrt{ \frac{25}{36} } + ( \sqrt{361} {)}^{2} - 4 \times \sqrt{0.49} \times \sqrt{100} = \frac{3}{5} \times \frac{5}{6} + 361 - 4 \times 0.7 \times 10 = \frac{1}{2} + 361 - 28 = 333 \frac{1}{2} [/tex]
