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Znajdź logarytmy.
[tex] log_{5}25[/tex]
[tex] log_{3}27[/tex]
[tex] log_{6}\frac{1}{6} [/tex]
[tex] log_{7}\frac{1}{49} [/tex]
[tex] log_{9}3[/tex]
[tex] log_{1000}10[/tex]
[tex] log_{5}\sqrt{5} [/tex]
[tex] log_{7}\sqrt[4]{7} [/tex]
[tex] log_{3}\sqrt[3]{3} [/tex]
[tex] log_{6}\sqrt[3]{36} [/tex]
[tex] log_{2}16[/tex]
[tex] log_{8}2[/tex]



Odpowiedź :

[tex]log_{5}25 = log_{5}5^{2} = 2\\\\log_{3}27 = log_{3}3^{3} = 3\\\\log_{6}\frac{1}{6} = log_{6} 6^{-1} = -1\\\\log_{7}\frac{1}{49} = log_{7}7^{-2} = -2\\\\log_{9} 3 = log_{9}9^{\frac{1}{2}} = \frac{1}{2}\\\\log_{1000} 10 = log_{1000} 1000^{\frac{1}{3}} = \frac{1}{3}\\\\log_{5} \sqrt{5} = log_{5} 5^{\frac{1}{2}} = \frac{1}{2}\\\\log_{7}\sqrt[4]{7} = log_{7} 7^{\frac{1}{4}} = \frac{1}{4}\\\\log_{3}\sqrt[3]{3} = log_{3} 3^{\frac{1}{3}} = \frac{1}{3}[/tex]

[tex]log_{6}\sqrt[3]{36} = log_{6} (6^{2})^{\frac{1}{3}} = log_{6} 6^{\frac{2}{3}} = \frac{2}{3}\\\\log_{2}16 = log_{2}2^{4} = 4\\\\log_{8}2 = log_{8}8^\frac{1}{3}} = \frac{1}{3}[/tex]

Odpowiedź:

Korzystam ze wzorów:

㏒ₐ a = 1

㏒ₐ bˣ = x㏒ₐ b

㏒ₐ b = x  z def. log. ⇒  aˣ = b

Szczegółowe wyjaśnienie:

Zobacz obrazek ZBIORJ