Odpowiedź :
1.
a)
[tex]\Delta = b^2 - 4ac = 2^2 - 4 \cdot 1 \cdot (-8) = 4 + 32 = 36\\x_1 = \frac{-b-\sqrt{\Delta} }{2a} = \frac{-2 - 6}{2} = \frac{-8}{2} = -4\\x_2 = \frac{-b+\sqrt{\Delta} }{2a} = \frac{-2 + 6}{2} = \frac{4}{2} = 2[/tex]
b)
[tex]f(x) = (x + 4)(x - 2)[/tex]
2.
[tex]q = \frac{-\Delta}{4a} = \frac{-36}{4} = -9[/tex]