a)
[tex] \frac{2 \frac{1}{3} \div 7 }{3.5} + \frac{4}{3 \frac{3}{5} \times 0.2} = \frac{ \frac{7}{3} \times \frac{1}{7} }{3.5} + \frac{4}{ \frac{18}{5} \times \frac{2}{10} } = \frac{1}{3} \div 3 \frac{1}{2} + \frac{4}{ \frac{18}{25} } = \frac{1}{3} \times \frac{2}{7} + 4 \times \frac{25}{18} = \frac{2}{21} + \frac{50}{9} = \frac{6}{63} + \frac{350}{63} = \frac{356}{63} = 5 \frac{41}{63} [/tex]
b)
[tex]0.04 - \frac{(2 \frac{1}{4} - 2.2) \div \frac{5}{4} }{(2 \frac{1}{8} - (2 - \frac{1}{2} ) \div \frac{4}{3} ) \times 1 \frac{3}{5} + 2 } = \frac{4}{100} - \frac{ (\frac{9}{4} - \frac{11}{5}) \times \frac{4}{5} }{ (\frac{17}{8} - \frac{3}{2} \times \frac{3}{4}) \times \frac{8}{5} + 2 } = \frac{1}{25} - \frac{( \frac{45}{20} - \frac{44}{20}) \times \frac{4}{5} }{( \frac{17}{8} - \frac{9}{8} ) \times \frac{8}{5} + 2} = \frac{1}{25} - \frac{ \frac{1}{20} \times \frac{4}{5} }{ \frac{8}{5} + 2 } = \frac{1}{25} - \frac{ \frac{1}{25} }{ \frac{8}{5} + \frac{10}{5} } = \frac{1}{25} - \frac{ \frac{1}{25} }{ \frac{18}{5} } = \frac{1}{25} - ( \frac{1}{25} \times \frac{5}{18} ) = \frac{1}{25} - \frac{1}{90} = \frac{18}{450} - \frac{5}{450} = \frac{13}{450} [/tex]
c)
[tex] \frac{( \frac{5}{3} - 1 \frac{1}{2} ) \div (1 \frac{1}{2} - \frac{5}{3} )}{(21 \frac{1}{3} - 17 \frac{5}{6} ) \times 3 \frac{3}{5} } = \frac{( \frac{5}{3} - \frac{3}{2}) \div ( \frac{3}{2} - \frac{5}{3} ) }{ (\frac{64}{3} - \frac{107}{6} ) \times \frac{18}{5} } = \frac{( \frac{10}{6} - \frac{9}{6}) \div (\frac{9}{6} - \frac{10}{6}) }{( \frac{128}{6} - \frac{107}{6}) \times \frac{18}{5} } = \frac{ \frac{1}{6} \times ( - 6)}{ \frac{21}{6} \times \frac{18}{5} } = \frac{ - 1}{ \frac{63}{5} } = - 1 \times \frac{5}{63} = - \frac{5}{63} [/tex]
d)
[tex](2 \frac{5}{6} + \frac{3}{4} \div ( \frac{2 \frac{1}{4} }{3 \frac{1}{2} \times 8 - 25} - 1 )) \times 4 \frac{4}{5} = ( \frac{17}{6} + \frac{3}{4} \div ( \frac{ \frac{9}{4} }{28 - 25} - 1)) \times \frac{24}{5} = ( \frac{17}{6} + \frac{3}{4} \div ( \frac{9}{4} \times \frac{1}{3} - 1)) \times \frac{24}{5} = ( \frac{17}{6} + \frac{3}{4} \div ( \frac{3}{4} - 1)) \times \frac{24}{5} = ( \frac{17}{6} + \frac{3}{4} \div ( - \frac{1}{4} )) \times \frac{24}{5} = ( \frac{17}{6} + \frac{3}{4} \times ( - 4)) \times \frac{24}{5} = ( \frac{17}{6} - 3) \times \frac{24}{5} = ( \frac{17}{6} - \frac{18}{6} ) \times \frac{24}{5} = - \frac{1}{6} \times \frac{24}{5} = - \frac{4}{5} [/tex]
e)
[tex]((2.37 + 3.03) \div 0.09 + 12 \frac{3}{5} \div 7 - 15.9 - \frac{13}{20} ) \div 36 \frac{1}{5} = ( \frac{54}{10} \times \frac{100}{9} + \frac{63}{5} \times \frac{1}{7} - 15.9 - \frac{13}{20} ) \times \frac{5}{181} = (60 + \frac{9}{5} - 15.9 - \frac{13}{20} ) \times \frac{5}{181} = (60 + \frac{18}{10} - 15.9 - \frac{65}{100}) \times \frac{5}{181} = (60 + 1.8 - 15.9 - 0.65) \times \frac{5}{181} = 45.25 \times \frac{5}{181} = 45 \frac{1}{4} \times \frac{5}{181} = \frac{181}{4} \times \frac{5}{181} = \frac{5}{4} = 1 \frac{1}{4} [/tex]
